Optimal. Leaf size=202 \[ \frac {c (2 a c-b d) \left (a+\frac {b}{x}\right )^{1+n}}{a d^2 (a c-b d) \left (d+\frac {c}{x}\right )}+\frac {\left (a+\frac {b}{x}\right )^{1+n} x}{a d \left (d+\frac {c}{x}\right )}+\frac {c^2 (2 a c-b d (2-n)) \left (a+\frac {b}{x}\right )^{1+n} \, _2F_1\left (1,1+n;2+n;\frac {c \left (a+\frac {b}{x}\right )}{a c-b d}\right )}{d^3 (a c-b d)^2 (1+n)}-\frac {(2 a c-b d n) \left (a+\frac {b}{x}\right )^{1+n} \, _2F_1\left (1,1+n;2+n;1+\frac {b}{a x}\right )}{a^2 d^3 (1+n)} \]
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Rubi [A]
time = 0.17, antiderivative size = 202, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 7, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.350, Rules used = {528, 382, 105,
156, 162, 67, 70} \begin {gather*} -\frac {\left (a+\frac {b}{x}\right )^{n+1} (2 a c-b d n) \, _2F_1\left (1,n+1;n+2;\frac {b}{a x}+1\right )}{a^2 d^3 (n+1)}+\frac {c^2 \left (a+\frac {b}{x}\right )^{n+1} (2 a c-b d (2-n)) \, _2F_1\left (1,n+1;n+2;\frac {c \left (a+\frac {b}{x}\right )}{a c-b d}\right )}{d^3 (n+1) (a c-b d)^2}+\frac {c (2 a c-b d) \left (a+\frac {b}{x}\right )^{n+1}}{a d^2 \left (\frac {c}{x}+d\right ) (a c-b d)}+\frac {x \left (a+\frac {b}{x}\right )^{n+1}}{a d \left (\frac {c}{x}+d\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 67
Rule 70
Rule 105
Rule 156
Rule 162
Rule 382
Rule 528
Rubi steps
\begin {align*} \int \frac {\left (a+\frac {b}{x}\right )^n x^2}{(c+d x)^2} \, dx &=\int \frac {\left (a+\frac {b}{x}\right )^n}{\left (d+\frac {c}{x}\right )^2} \, dx\\ &=-\text {Subst}\left (\int \frac {(a+b x)^n}{x^2 (d+c x)^2} \, dx,x,\frac {1}{x}\right )\\ &=\frac {\left (a+\frac {b}{x}\right )^{1+n} x}{a d \left (d+\frac {c}{x}\right )}+\frac {\text {Subst}\left (\int \frac {(a+b x)^n (2 a c-b d n+b c (1-n) x)}{x (d+c x)^2} \, dx,x,\frac {1}{x}\right )}{a d}\\ &=\frac {c (2 a c-b d) \left (a+\frac {b}{x}\right )^{1+n}}{a d^2 (a c-b d) \left (d+\frac {c}{x}\right )}+\frac {\left (a+\frac {b}{x}\right )^{1+n} x}{a d \left (d+\frac {c}{x}\right )}+\frac {\text {Subst}\left (\int \frac {(a+b x)^n ((a c-b d) (2 a c-b d n)-b c (2 a c-b d) n x)}{x (d+c x)} \, dx,x,\frac {1}{x}\right )}{a d^2 (a c-b d)}\\ &=\frac {c (2 a c-b d) \left (a+\frac {b}{x}\right )^{1+n}}{a d^2 (a c-b d) \left (d+\frac {c}{x}\right )}+\frac {\left (a+\frac {b}{x}\right )^{1+n} x}{a d \left (d+\frac {c}{x}\right )}-\frac {\left (c^2 (2 a c-b d (2-n))\right ) \text {Subst}\left (\int \frac {(a+b x)^n}{d+c x} \, dx,x,\frac {1}{x}\right )}{d^3 (a c-b d)}+\frac {(2 a c-b d n) \text {Subst}\left (\int \frac {(a+b x)^n}{x} \, dx,x,\frac {1}{x}\right )}{a d^3}\\ &=\frac {c (2 a c-b d) \left (a+\frac {b}{x}\right )^{1+n}}{a d^2 (a c-b d) \left (d+\frac {c}{x}\right )}+\frac {\left (a+\frac {b}{x}\right )^{1+n} x}{a d \left (d+\frac {c}{x}\right )}+\frac {c^2 (2 a c-b d (2-n)) \left (a+\frac {b}{x}\right )^{1+n} \, _2F_1\left (1,1+n;2+n;\frac {c \left (a+\frac {b}{x}\right )}{a c-b d}\right )}{d^3 (a c-b d)^2 (1+n)}-\frac {(2 a c-b d n) \left (a+\frac {b}{x}\right )^{1+n} \, _2F_1\left (1,1+n;2+n;1+\frac {b}{a x}\right )}{a^2 d^3 (1+n)}\\ \end {align*}
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Mathematica [A]
time = 0.24, size = 179, normalized size = 0.89 \begin {gather*} \frac {\left (a+\frac {b}{x}\right )^{1+n} \left (a c d (a c-b d) (2 a c-b d) (1+n) x+a d^2 (a c-b d)^2 (1+n) x^2+(c+d x) \left (a^2 c^2 (2 a c+b d (-2+n)) \, _2F_1\left (1,1+n;2+n;\frac {c \left (a+\frac {b}{x}\right )}{a c-b d}\right )-(a c-b d)^2 (2 a c-b d n) \, _2F_1\left (1,1+n;2+n;1+\frac {b}{a x}\right )\right )\right )}{a^2 d^3 (a c-b d)^2 (1+n) (c+d x)} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.06, size = 0, normalized size = 0.00 \[\int \frac {\left (a +\frac {b}{x}\right )^{n} x^{2}}{\left (d x +c \right )^{2}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{2} \left (a + \frac {b}{x}\right )^{n}}{\left (c + d x\right )^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^2\,{\left (a+\frac {b}{x}\right )}^n}{{\left (c+d\,x\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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